Advertisements
Advertisements
Question
Find the axis, vertex, focus, equation of directrix and the length of latus rectum of the parabola (y - 2)2 = 4(x - 1)
Solution
Given equation of the parabola is (y - 2)2 = 4(x - 1)
⇒ y2 = 4X where X = x - 1 and Y = y - 2
⇒ 4a = 4
⇒ a = 1
Referred to (X, Y) |
Referred to (x, y) x = X + 1, Y = y + 2 |
|
Axis | X-axis ⇒ Y = 0 |
y - 2 = 0 ⇒ y = 2 |
Vertex | (0, 0) | (1, 2) |
Focus (0, 0) | (1, 0) | (2, 2) |
Equation of directrix | X = - a ⇒ X = - 1 |
x - 1 = - 1 ⇒ x = 0 |
Length of latus rectum |
4a = 4 | 4 |
APPEARS IN
RELATED QUESTIONS
Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola
x2 = 8y
Find the co-ordinates of the focus, vertex, equation of the directrix, axis and the length of latus rectum of the parabola
x2 = - 16y
The average variable cost of the monthly output of x tonnes of a firm producing a valuable metal is ₹ `1/5`x2 – 6x + 100. Show that the average variable cost curve is a parabola. Also, find the output and the average cost at the vertex of the parabola.
Find the equation of the parabola in the cases given below:
End points of latus rectum (4, – 8) and (4, 8)
Find the equation of the ellipse in the cases given below:
Length of latus rectum 8, eccentricity = `3/5` centre (0, 0) and major axis on x-axis
Find the vertex, focus, equation of directrix and length of the latus rectum of the following:
x2 = 24y
Find the vertex, focus, equation of directrix and length of the latus rectum of the following:
y2 – 4y – 8x + 12 = 0
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`(x + 1)^2/100 + (y - 2)^2/64` = 1
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
18x2 + 12y2 – 144x + 48y + 120 = 0
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
9x2 – y2 – 36x – 6y + 18 = 0