Advertisements
Advertisements
Question
Find the class-mark of the class 35-40.
Advertisements
Solution
Class mark = `("Lower class limit" + "Upper class limit")/2`
Since, `(35 + 40)/2`
= `75/2`
= 37.5
So, the class mark for the class 35-40 is 37.5.
APPEARS IN
RELATED QUESTIONS
If class mark is 10 and class width is 6 then find the class.
In the table given below, class-mark and frequencies are given. Construct the frequency table taking inclusive and exclusive classes.
| Class width | Frequency |
| 5 | 3 |
| 15 | 9 |
| 25 | 15 |
| 35 | 13 |
The value of π up to 50 decimal place is
3.14159265358979323846264338327950288419716939937510
(i) Make a frequency distribution table of digits from 0 to 9 after the decimal place.
(ii) Which are the most and least occurring digits?
Construct a frequency distribution table from the following cumulative frequency distribution:
| Class Interval | Cumulative Frequency |
| 10 - 19 | 8 |
| 20 - 29 | 19 |
| 30- 39 | 23 |
| 40- 49 | 30 |
Construct a cumulative frequency distribution table from the frequency table given below:
| Class Interval | Frequency |
| 0 -8 | 9 |
| 8 - 16 | 13 |
| 16 - 24 | 12 |
| 24 - 32 | 7 |
| 32 - 40 | 15 |
Given below are the marks obtained by 30 students in an examination:
|
08 |
17 |
33 |
41 |
47 |
23 |
20 |
34 |
|
09 |
18 |
42 |
14 |
30 |
19 |
29 |
11 |
|
36 |
48 |
40 |
24 |
22 |
02 |
16 |
21 |
|
15 |
32 |
47 |
44 |
33 |
01 |
Taking class intervals 1 - 10, 11 - 20, ....., 41 - 50; make a frequency table for the above distribution.
Construct a frequency distribution table from the following cumulative frequency distribution:
| C.I | C.F |
| 5 - 10 | 18 |
| 10 - 15 | 30 |
| 15 - 20 | 46 |
| 20 - 25 | 73 |
| 25 - 30 | 90 |
Inclusive series is a continuous series
Form a continuous frequency distribution table for the marks obtained by 30 students in a X std public examination.
328, 470, 405, 375, 298, 326, 276, 362, 410, 255, 391, 370, 455, 229, 300, 183, 283, 366, 400, 495, 215, 157, 374, 306, 280, 409, 321, 269, 398, 200
Size of the class 150 – 175 is ______.
Tally marks are used to find ______.
Upper limit of class interval 75 – 85 is ______.
In the class interval 26 – 33, 33 is known as ______.
The number of times a particular observation occurs in a given data is called its ______.
Using the following frequency table.
| Marks (obtained out of 10) | 4 | 5 | 7 | 8 | 9 | 10 |
| Frequency | 5 | 10 | 8 | 6 | 12 | 9 |
The frequency of more than 8 marks is 21.
Given below is a frequency distribution table. Read it and answer the questions that follow:
| Class Interval | Frequency |
| 10 – 20 | 5 |
| 20 – 30 | 10 |
| 30 – 40 | 4 |
| 40 – 50 | 15 |
| 50 – 60 | 12 |
- What is the lower limit of the second class interval?
- What is the upper limit of the last class interval?
- What is the frequency of the third class?
- Which interval has a frequency of 10?
- Which interval has the lowest frequency?
- What is the class size?
The marks obtained (out of 20) by 30 students of a class in a test are as follows:
14, 16, 15, 11, 15, 14, 13, 16, 8, 10, 7, 11, 18, 15, 14, 19, 20, 7, 10, 13, 12, 14, 15, 13, 16, 17, 14, 11, 10, 20.
Prepare a frequency distribution table for the above data using class intervals of equal width in which one class interval is 4 – 8 (excluding 8 and including 4).
Complete the following table:
| Weights (in kg.) |
Tally Marks | Frequency (Number of persons) |
| 40 – 50 | `\cancel(bb|bb|bb|bb|) \cancel(bb|bb|bb|bb|) bb|bb|` | |
| 50 – 60 | `\cancel(bb|bb|bb|bb|) \cancel(bb|bb|bb|bb|) bb|bb|bb|bb|` | |
| 60 – 70 | `\cancel(bb|bb|bb|bb|) bb|` | |
| 70 – 80 | `bb|bb|` | |
| 80 – 90 | `bb|` |
Find the total number of persons whose weights are given in the above table.
