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Question
Find the empirical formula of the compounds with the following percentage composition:
Pb = 62.5%, N = 8.5%, O = 29.0%
Solution
| Element | Percentage | Atomic Weight | Ratio | Simplest Ratio |
| Pb | 62.5 | 207 | `62.5/207` = 0.302 | `0.302/0.302` = 1 |
| N | 8.5 | 14 | `8.5/14` = 0.608 | `0.608/0.302` = 2 |
| O | 29.0 | 16 | `29.0/16` = 1.812 | `1.812/0.302` = 6 |
∴ The empirical formula of the given compound = PbN2O6 or Pb(NO3)2
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