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Tamil Nadu Board of Secondary EducationHSC Science Class 11

Find the equations of straight lines which are perpendicular to the line 3x + 4y − 6 = 0 and are at a distance of 4 units from (2, 1) - Mathematics

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Question

Find the equations of straight lines which are perpendicular to the line 3x + 4y − 6 = 0 and are at a distance of 4 units from (2, 1)

Sum

Solution

The equation of the given line is

3x + 4y – 6 = 0   ......(1)

The equation of any line perpendicular to line (1) is

4x – 3y + k = 0   ......(2)

Given that this line is 4 units from the point (2, 1)

∴ 4 = `+-  (4(2) - 3(1) + k")/sqrt(4^2 + ( - 3)^2`

± 4 = `(8 - 3 + "k")/sqrt(16 + 9)`

± 4 = `(5 + "k")/5`

5 + k = ± 20

k = ± 20 – 5

k = 20 – 5 or k = -20

k = 15 or k = – 25

∴ The equation of the required lines are

4x – 3y + 15 = 0 and 4x – 3y – 25 = 0

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Chapter 6: Two Dimensional Analytical Geometry - Exercise 6.3 [Page 271]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 11 TN Board
Chapter 6 Two Dimensional Analytical Geometry
Exercise 6.3 | Q 8 | Page 271

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