English
Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10

Find the L.C.M. of the given expressions – 9a3b2, 12a2b2c - Mathematics

Advertisements
Advertisements

Question

Find the L.C.M. of the given expressions

– 9a3b2, 12a2b2c

Sum

Solution

– 9a3b2 = – (32 × a3 × b2)

12a2b2c = 22 × 3 × a2 × b2 × c

L.C.M. = – (22 × 32 × a3 × b2 × c)

= – 36a3b2c

shaalaa.com
GCD and LCM of Polynomials
  Is there an error in this question or solution?
Chapter 3: Algebra - Exercise 3.2 [Page 97]

APPEARS IN

Samacheer Kalvi Mathematics [English] Class 10 SSLC TN Board
Chapter 3 Algebra
Exercise 3.2 | Q 2. (ii) | Page 97
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×