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Find the smallest square number divisible by each one of the numbers 8, 9 and 10. - Mathematics

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Question

Find the smallest square number divisible by each one of the numbers 8, 9 and 10.

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Sum

Solution

Given: The least-square number which is exactly divisible by 8, 9 and 10 is equal to L.C.M. of 8, 9 and 10.

2 8, 9, 10
2 4, 9, 5
2 2, 9, 5
3 1, 9, 5
3 1, 3, 5
5 1, 1, 5
  1, 1, 1

Hence, their L.C.M. is 2 × 2 × 2 × 3 × 3 × 5 = 360

As we see, (2 × 2) × 2 × (3 × 3) × 5

i.e. 2 and 5 is not able to make their pair.

Hence, to make it perfect square, it must be multiplied with 2 × 5 = 10

As, 360 × 10 = 3600

Hence, 3600 is least square number which is exactly divisible by 8, 9 and 10.

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Chapter 3: Square-Square Root and Cube-Cube Root - Exercise [Page 96]

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NCERT Exemplar Mathematics [English] Class 8
Chapter 3 Square-Square Root and Cube-Cube Root
Exercise | Q 131. | Page 96

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