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Question
Find the square of `(3a)/(2b) - (2b)/(3a)`.
Sum
Solution
We know that,
(a - b)2 = a2 + b2 - 2ab
`(3a)/(2b) - (2b)/(3a) = [(3a)/(2b)]^2 + [(2b)/(3a)]^2 - 2 xx (3a)/(2b) xx (2b)/(3a)`
= `(9a^2)/(4b^2) + (4b^2)/(9a^2) - 2`
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