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Find the sum: 4-1n+4-2n+4-3n+... upto n terms - Mathematics

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Question

Find the sum:

`4 - 1/n + 4 - 2/n + 4 - 3/n + ...` upto n terms

Sum

Solution

Here, first term, a = `4 - 1/n`

Common difference,

d = `(4 - 2/n) - (4 - 1/n)`

= `(-2)/n + 1/n`

= `(-1)/n`

∵ Sum of n terms of an AP,

Sn = `n/2[2a + (n - 1)d]`

⇒ Sn = `n/2[2(4 - 1/n) + (n - 1)((-1)/n)]`

= `n/2{8 - 2/n - 1 + 1/n}`

= `n/2(7 - 1/n)`

= `n/2 xx ((7n - 1)/n)`

= `(7n - 1)/2`

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Chapter 5: Arithematic Progressions - Exercise 5.3 [Page 53]

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NCERT Exemplar Mathematics [English] Class 10
Chapter 5 Arithematic Progressions
Exercise 5.3 | Q 21.(ii) | Page 53
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