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Question
Find the sum and product of the roots for the following quadratic equation
`3 + 1/"a" = 10/"a"^2`
Solution
3a2 + a = 10
3a2 + a – 10 = 0 comparing this with x2 – (α + β)
x + αβ = 0
`"a"^2 - (- 1/3)"a" + ((-10)/3)` = 0
α + β = `(-1)/(3)`
αβ = `(-10)/(3)`
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