Advertisements
Advertisements
Question
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = kx2 – 3x + k
Solution
If x − 1 is a factor of polynomial p(x), then p(1) must be 0.
p(x) = kx2 − 3x + k
⇒ p(1) = 0
⇒ k(1)2 − 3(1) + k = 0
⇒ k − 3 + k = 0
⇒ 2k − 3 = 0
⇒ k = `3/2`
Therefore, the value of k is `3/2`.
APPEARS IN
RELATED QUESTIONS
Find the value of k, if x – 1 is a factor of p(x) in the following case:
p(x) = `kx^2 - sqrt2x +1`
Factorise:
12x2 – 7x + 1
Factorise:
x3 – 3x2 – 9x – 5
Determine the following polynomial has (x + 1) a factor:
x4 + x3 + x2 + x + 1
Find the factor of the polynomial given below.
`1/2x^2 - 3x + 4`
Show that x + 3 is a factor of 69 + 11x – x2 + x3.
If x + 1 is a factor of ax3 + x2 – 2x + 4a – 9, find the value of a.
Factorise the following:
1 – 64a3 – 12a + 48a2
Factorise:
a3 – 8b3 – 64c3 – 24abc
If both x – 2 and `x - 1/2` are factors of px2 + 5x + r, show that p = r.
