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Question
Find the values of the following polynomials at a = –2 and b = 3:
a3 – 3a2b + 3ab2 – b3
Solution
Given, a = –2 and b = 3
So, putting a = –2 and b = 3 in the given expressions, we get
a3 – 3a2b + 3ab2 – b3 = (–2)3 –3(–2)2(3) + 3(–2)(3)2 – (3)3
= – 8 – 36 – 54 – 27
= –125
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