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Question
Find the values of x, y, z if `[(x - 3, 3x - z),(x + y + 7, x + y + z)] = [(1, 0),(1, 6)]`
Solution
x – 3 = 1 ⇒ x = 1 + 3 ⇒ x = 4
3x – z = 0 ...(substitute the value of x)
3(4) – z = 0
12 – z = 0
∴ z = 12
x + y + z = 6
4 + y + 12 = 0
y + 16 = 6
y = 6 – 16
∴ y = – 10
The value of x = 4, y = – 10 and z = 12
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