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Question
Find the volume of a cube whose diagonals is `sqrt(48)"cm"`.
Solution
Given that:
Diagonal of a cube = `sqrt(48)"cm"`
i.e., `sqrt(3) xx "l" = sqrt(48)` ...[∵ Diagonal of cube = `sqrt(3) xx "l"]`
l = `sqrt(48)/sqrt(3)`
l = `sqrt(48/3)`
= `sqrt(16)`
= 4cm
∴ Side (l) = 4cm
Now,
Volume of cube
= l3
= l x l x l
= 4 x 4 x 4
= 16 x 4
= 64cm3
∴ Volume of Cube = 64cm3.
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