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Question
Find the x and y-intercepts of the following line: 2x – 3y + 12 = 0
Solution
Given equation of the line is 2x – 3y + 12 = 0
∴ 2x – 3y = – 12
∴ `(2x)/((-12)) - (3y)/((-12)` = 1
∴ `x/(-6) + y/4` = 1
This is of the form `x/"a" + y/"b"` = 1,
where x-intercept = a, y-intercept = b
∴ x-intercept = 6 and y-intercept = 4.
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