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Question
Find the tow consecutive positive odd integer whose product s 483.
Solution
Let the two consecutive positive odd integers be x and (x +2).
According to the given condition,
`x(x+2)=483`
⇒`x^2+2x-483=0`
⇒`x^2+23x-21x-483=0`
⇒`x(x+23)-21(x+21)=0`
⇒`(x+23) (x+21)=0`
⇒`x+23=0 or x-21=0`
⇒`x=-23 or x=21`
∴ x =21 (x is a positive odd integer)
When `x=21`
`x+2=21+2=23`
Hence, the required integers are 21 and 23.
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