Advertisements
Advertisements
Question
Find the two consecutive positive even integers whose product is 288.
Solution
Let the two consecutive positive even integers be x and(x+2)
According to the given condition,
`x(x+2)=288`
⇒`x^2+2x-288=0`
⇒`x^2+18x-16x-288=0`
⇒`x(x+18)-16(x+18)=0`
⇒`(x+18)(x-16)=0`
⇒`x+18=0 or x-16=0`
⇒`x=-18 or x=16`
`∴x=16 ` (x is a positive even integer)
When` x=16 `
`x+2=16+2=18`
Hence, the required integers are 16 and 18.
APPEARS IN
RELATED QUESTIONS
Solve the following quadratic equations by factorization:
6x2 - x - 2 = 0
Find the two consecutive natural numbers whose product is 20.
Two number differ by 4 and their product is 192. Find the numbers?
The sum of two numbers is 18. The sum of their reciprocals is 1/4. Find the numbers.
Solve the following quadratic equation by factorisation.
2y2 + 27y + 13 = 0
Solve the following equation: 25x (x + 1) = -4
Find the factors of the Polynomial 3x2 - 2x - 1.
Write the number of zeroes in the end of a number whose prime factorization is 22 × 53 × 32 × 17.
In each of the following determine whether the given values are solutions of the equation or not.
9x2 - 3x - 2 = 0; x = `-(1)/(3), x = (2)/(3)`
4x2 – 9 = 0 implies x is equal to ______.
