Advertisements
Advertisements
Question
Write the number of zeroes in the end of a number whose prime factorization is 22 × 53 × 32 × 17.
Solution
Given prime factorization is 22×53×32×17">22 × 53 × 32 ×17.
A number will have zero at the end when we have 2×5">2 × 5.
In 22×53×32×17">22 × 53 × 32 × 17, we will have 2 zeroes as 22×52×5×32×17">(22 × 52) × 5 × 32 × 17.
RELATED QUESTIONS
Solve for x : `(x+1)/(x-1)+(x-1)/(x+2)=4-(2x+3)/(x-2);x!=1,-2,2`
Solve the following quadratic equations by factorization:
`(x+1)/(x-1)-(x-1)/(x+1)=5/6` , x ≠ 1, x ≠ -1
Find the two consecutive natural numbers whose product is 20.
Solve each of the following equations by factorization:
`9/2x=5+x^2`
The sum of the squares to two consecutive positive odd numbers is 514. Find the numbers.
If \[x = - \frac{1}{2}\],is a solution of the quadratic equation \[3 x^2 + 2kx - 3 = 0\] ,find the value of k.
Solve the following by reducing them to quadratic form:
`sqrt(y + 1) + sqrt(2y - 5) = 3, y ∈ "R".`
Solve the following equation by factorization
2x2 – 9x + 10 = 0,when x∈N
Find two consecutive odd integers such that the sum of their squares is 394.
Solve the following quadratic equation by factorisation method:
x2 + x – 20 = 0