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Question
In each of the following determine whether the given values are solutions of the equation or not.
9x2 - 3x - 2 = 0; x = `-(1)/(3), x = (2)/(3)`
Solution
Given equation is
9x2 - 3x - 2 = 0; x = `-(1)/(3), x = (2)/(3)`
Substitute x = `-(1)/(3)` in the L.H.S.
L.H.S. = `9(-1/3)^2 - 3 xx (-1/3) -2`
= `9 xx (1)/(9) + 1 - 2`
= 2 - 2
= 0
= R.H.S.
Hence, x = `-(1)/(3)` is a solution of the equation.
Again put x = `(2)/(3)`
L.H.S. = `9(2/3)^2 -3(2/3)-2`
= `9 xx (4)/(9) - 2 -2`
= 4 - 4
= 0
= R.H.S.
Hence, x = `(2)/(3)` is a solution of the equation.
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