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Question
Find two numbers such that one of them exceeds the other by 18 and their sum is 92.
Solution
Let one of the numbers be x.
∴ The other number = (x + 18)
According to the question:
x + (x + 18) = 92
or, 2x + 18 − 18 = 92 − 18 [Subtracting 18 from both the sides]
or, 2x =74
or, `(2x)/2=74/2` [Dividing both the sides by 2]
or, x = 37
Required numbers are:
x = 37
or, x + 18 = 37 + 18 = 55
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