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Question
Find the value of the discriminant in the following quadratic equation :
10 x - `1/x` = 3
Solution
10 x - `1/x` = 3
10x2 - 3x - 1 = 0
Discriminant = b2 - 4ac
= (-3)2 - 4 (10) (-1)
= 9+ 40
= 49
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