Advertisements
Advertisements
Question
Find the value of p for the following distribution whose mean is 16.6
| x: | 8 | 12 | 15 | p | 20 | 25 | 30 |
| f : | 12 | 16 | 20 | 24 | 16 | 8 | 4 |
Solution
| x | f | fx |
| 8 | 12 | 96 |
| 12 | 16 | 192 |
| 15 | 20 | 300 |
| p | 24 | 24p |
| 20 | 16 | 320 |
| 25 | 8 | 200 |
| 30 | 4 | 120 |
| N = 100 | `sumfx = 24P + `1228` | |
Given mean = 16.6
⇒ `(sumfx)/N = 16.6`
⇒ `24p + 1228 / 100 = 16.6`
⇒ 24p = 1660 - 1228
⇒ 24p = 1660 - 1228
⇒ 24p = 432
⇒ `p = 432/24 = 18`
APPEARS IN
RELATED QUESTIONS
Find the mean of x, x + 2, x + 4, x +6, x + 8.
The numbers of children in 10 families of a locality are:
2, 4, 3, 4, 2, 0, 3, 5, 1, 1, 5. Find the mean number of children per family.
If the mean of the following data is 15, find p.
| x: | 5 | 10 | 15 | 20 | 25 |
| f : | 6 | p | 6 | 10 | 5 |
Find the missing frequency (p) for the following distribution whose mean is 7.68.
| x | 3 | 5 | 7 | 9 | 11 | 13 |
| f | 6 | 8 | 15 | p | 8 | 4 |
Find the median of the following data (1-8)
15, 6, 16, 8, 22, 21, 9, 18, 25
If the mean of x + 2, 2x + 3, 3x + 4, 4x + 5 is x + 2, find x.
The mean salary of 20 workers is Rs.10,250. If the salary of office superintendent is added, the mean will increase by Rs.750. Find the salary of the office superintendent.
A grouped frequency distribution table with classes of equal sizes using 63 – 72 (72 included) as one of the class is constructed for the following data:
30, 32, 45, 54, 74, 78, 108, 112, 66, 76, 88, 40, 14, 20, 15, 35, 44, 66, 75, 84, 95, 96, 102, 110, 88, 74, 112, 14, 34, 44.
The number of classes in the distribution will be:
If `barx_1, barx_2, barx_3, ..., barx_n` are the means of n groups with n1, n2, ..., nn number of observations respectively, then the mean `barx` of all the groups taken together is given by ______.
There are 50 numbers. Each number is subtracted from 53 and the mean of the numbers so obtained is found to be –3.5. The mean of the given numbers is ______.
