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Question
Find x, if `[x, -5, -1][(1,0,2),(0,2,1),(2,0,3)][(x),(4),(1)] = O`
Solution
`[x -5 -1][(1,0,2), (0,2,1), (2,0,3)][(x),(4),(1)] = [0]`
∴ `[x -5 -1][(x + 0 + 2), (0 + 8 + 1), (2x + 0 + 3)] = [0]`
⇒ [x -5 -1]`[(x + 2), (9), (2x + 3)] = [0]`
⇒ [x(x + 2) - 45 - (2x + 3)] = 0
⇒ x2 + 2x - 45 - (2x + 3) = 0
⇒ x2 + 2x - 45 - 2x - 3 = 0
⇒ x2 - 48 = 0
⇒ x2 = 48
⇒ x = ±`sqrt48`
`= 4sqrt3`
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