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Question
For the following number, find the smallest whole number by which it should be divided so as to get a perfect square number. Also find the square root of the square number so obtained.
2645
Solution
2645 can be factorised as follows:
5 | 2645 |
23 | 529 |
23 | 23 |
1 |
2645 = 5 × 23 × 23
Here, prime factor 5 does not have its pair.
If we divide this number by 5, then the number will become a perfect square.
Therefore, 2645 has to be divided by 5 to obtain a perfect square.
2645 ÷ 5 = 529 is a perfect square.
529 = 23 × 23
∴ `sqrt529` = 23
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