Advertisements
Advertisements
Question
For the ground state, the electron in the H-atom has an angular momentum = h, according to the simple Bohr model. Angular momentum is a vector and hence there will be infinitely many orbits with the vector pointing in all possible directions. In actuality, this is not true ______.
Options
because Bohr model gives incorrect values of angular momentum.
because only one of these would have a minimum energy.
angular momentum must be in the direction of spin of electron.
because electrons go around only in horizontal orbits.
Solution
For the ground state, the electron in the H-atom has an angular momentum = h, according to the simple Bohr model. Angular momentum is a vector and hence there will be infinitely many orbits with the vector pointing in all possible directions. In actuality, this is not true because Bohr model gives incorrect values of angular momentum.
Explanation:
Bohr found that the magnitude of the electron’s angular momentum is quantized i.e. L = `mv_nr_n = n(h/(2pi))` where n = 1, 2 , 3, ...... each value of n corresponds to a permitted value of the orbit radius. rn = Radius of nth orbit, vn = corresponding speed
Bohr’s model gives only the magnitude of angular momentum. The angular momentum is a vector quantity. Hence we cannot express angular momentum completely by the Bohr model. Hence it does not give correct values of angular momentum of a revolving electron.
APPEARS IN
RELATED QUESTIONS
Using Bohr's postulates of the atomic model, derive the expression for radius of nth electron orbit. Hence obtain the expression for Bohr's radius.
Calculate the magnetic dipole moment corresponding to the motion of the electron in the ground state of a hydrogen atom.
If l3 and l2 represent angular momenta of an orbiting electron in III and II Bohr orbits respectively, then l3: l2 is :
Hydrogen atom has only one electron, so mutual repulsion between electrons is absent. However, in multielectron atoms mutual repulsion between the electrons is significant. How does this affect the energy of an electron in the orbitals of the same principal quantum number in multielectron atoms?
The inverse square law in electrostatics is |F| = `e^2/((4πε_0).r^2)` for the force between an electron and a proton. The `(1/r)` dependence of |F| can be understood in quantum theory as being due to the fact that the ‘particle’ of light (photon) is massless. If photons had a mass mp, force would be modified to |F| = `e^2/((4πε_0)r^2) [1/r^2 + λ/r]`, exp (– λr) where λ = mpc/h and h = `h/(2π)`. Estimate the change in the ground state energy of a H-atom if mp were 10-6 times the mass of an electron.
The radius of the innermost electron orbit of a hydrogen atom is 5.3 × 10–11m. The radius of the n = 3 orbit is ______.
The wavelength in Å of the photon that is emitted when an electron in Bohr orbit with n = 2 returns to orbit with n = 1 in H atom is ______ Å. The ionisation potential of the ground state of the H-atom is 2.17 × 10−11 erg.
In Bohr's theory of hydrogen atom, the electron jumps from higher orbit n to lower orbit p. The wavelength will be minimum for the transition ______.
The total energy of an electron in the nth orbit of the hydrogen atom is proportional to ______.
What is meant by ionisation energy?