Advertisements
Advertisements
Question
From the diagram given below, calculate distance covered by body.
Solution
Distance covered = area under v.t. graph
= area of ΔOAC + area of ΔABC
= `1/2xx"OC"xx"AC"+1/2xx"BC"xx"AC"`
= `1/2xx10xx15+1/2xx6xx15`
= 5 × 15 + 3 × 15
= 75 + 45
= 120 m
APPEARS IN
RELATED QUESTIONS
Name the two quantities, the slope of whose graph give acceleration.
Draw a velocity-time graph to show the following motion :
A car accelerates uniformly from rest for 5 s ; then it travels at a steady’ velocity for 5 s.
Given alongside is the velocity-time graph for a moving body :
Find :
(i) Velocity of the body at point C.
(ii) Acceleration acting on the body between A and B.
(iii) Acceleration acting on the body between B and C.
What type of motion is represented by the following graph ?
Multiple choice Question. Select the correct option.
A graph is a straight line parallel to the time axis in a distance-time graph. From the graph, it implies:
Diagram shows a velocity – time graph for a car starting from rest. The graph has three sections AB, BC and CD.
Compare the distance travelled in section BC with the distance travelled in section AB.
Draw the following graph:
Speed versus time for a fluctuating speed.
Draw the following graph:
Speed versus time for a uniformly retarded motion.
Which of the following can determine the acceleration of a moving object.
If the velocity-time graph has the shape AMB, what would be the shape of the corresponding acceleration-time graph?