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Question
From the equation:
\[\ce{C + 2H2SO4 -> CO2 + 2H2O + 2SO2}\]
Calculate the volume of sulphur dioxide measured at STP, liberated at the same time.
Solution
\[\ce{\underset{12 g}{C2} + \underset{2(98)}{2H2SO4} -> CO2 + 2H2O + 2SO2}\]
12 g of carbon will liberate (22.4 × 2) litres of SO2
1 g of carbon will liberate `(22.4 xx 2)/12` litres of SO2
3 g of carbon will liberate `(22.4 xx 2)/12 xx 3` litres of SO2 = 11.2 litres of SO2
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