Advertisements
Advertisements
Question
Given A = {x : –1 < x ≤ 5, x ∈ R} and B = {x : – 4 ≤ x < 3, x ∈ R}
Represent on different number lines:
A ∩ B
Solution
A ∩ B = {x : –1 < x ≤ 3, x ∈ R}
It can be represented on a number line as
APPEARS IN
RELATED QUESTIONS
Solve the following in equation and represent the solution set on the number line.
`R - 3 < -1/2 - (2x)/3 <= 5/6, x ∈ R`
P is the solution set of 7x – 2 > 4x + 1 and Q is the solution set of 9x – 45 ≥ 5(x – 5); where x ∈ R. Represent:
- P ∩ Q
- P – Q
- P ∩ Q’ on the different number of lines.
Given that x ∈ I. solve the inequation and graph the solution on the number line:
`3 >= (x - 4)/2 + x/3 >= 2`
Solve the inequation:
3z – 5 ≤ z + 3 < 5z – 9, z ∈ R.
Graph the solution set on the number line.
Solve the following linear in-equation and graph the solution set on a real number line :
`4 3/4 >= "x" + 5/6 > 1/3` , x ∈ R
Give that x ∈ I. Solve the inequation and graph the solution on the number line:
`3≥(x - 4)/(2)+x/(3)≥2`
Graph the solution set for each inequality:
5 ≤ x < 10
Solve the following inequalities and represent the solution on a number line:
`(2x + 5)/(4) > (4 - 3x)/(6)`
Solve the following inequalities and represent the solution set on a number line:
-4 ≤ 2x - 3 ≤ 5
For the replacement set = {– 8, – 6, – 4, – 2, 0, 2, 4, 6, 8}, which of the following is not a solution set?