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Question
Greenlight is an incident at the polarising angle on a certain transparent medium. The angle of refraction is 30°.
Find
(i) polarising angle, and
(ii) refractive index of the medium.
Solution
(i) when the light is incident at the polarizing angle, the angle of refraction and angle of polarization are related according to the equation,
∠ip + ∠r = 90°
The angle of refraction is given as, 30°. So the angle of polarization, ∠ip = 90° - 30° = 60°
(ii) Applying Snell's law, we can write, the refractive index of the transparent media,` mu = sin"i"_"p"/sin "r"`
⇒ `mu = sin60^@/sin30^@ = (sqrt3/2)/(1/2) = sqrt3`
⇒ ` = mu sqrt3`
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