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Question
Half-life of a certain radioactive material is 8 hours.
Find the disintegration constant of this material.
Solution
`"T"_(1/2) = 0.693/lambda` [λ = Disintegration constant]
`therefore lambda = 0.693/8`
`therefore lambda = 0.693/(8 xx 60 xx 60)` s-1 = 2.41 × 10-5 s-1
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