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Question
Heart Rate : The heart rate is one of the 'vital signs' of health in the human body. It measures the number of times per minute that the heart contracts or beats. While a normal heart rate does not guarantee that a person is free of health problems, it is a useful benchmark for identifying a range of health issues.
Thirty women were examined by doctors of AIIMS and the number of heart beats per minute were recorded and summarized as follows:
Number of heart beats per minute | Number of Women |
65 − 68 | 2 |
68 − 71 | 4 |
71 − 74 | 3 |
74 − 77 | 8 |
77 − 80 | 7 |
80 − 83 | 4 |
83 − 86 | 2 |
Based on the above information, answer the following questions:
- How many women are having heart beat in the range 68 − 77? (1)
- What is the median class of heart beats per minute for these women? (1)
-
- Find the modal value of heart beats per minute for these women. (2)
OR - Find the median value of heart beats per minute for these women. (2)
- Find the modal value of heart beats per minute for these women. (2)
Solution
Number of heart beats per minute | Number of Women | Cumulative frequency |
65 − 68 | 2 | 2 |
68 − 71 | 4 | 6 |
71 − 74 | 3 | 9 |
74 − 77 | 8 | 17 |
77 − 80 | 7 | 24 |
80 − 83 | 4 | 28 |
83 − 86 | 2 | 30 |
Σ(f) = 30 |
(i) Number ot women having a heartbeat in range 68 − 77
⇒ 4 +3 + 8
= 15 ...(i)
(ii) Total frequency = 30
∴ `"N"/2`
= `30/2`
= 15
Since Cumulative Frequency greater than or equal to 15 is lies in class Interval 74 − 77
∴ Median class of heartbeats = 74 − 77.
(iii) (a) Mode = `l + (("f"_1 - "f"_0)/(2"f"_1 - "f"_0 - "f"_2)) xx "h"`
where,
Modal class having highest frequency = 74 − 77
l = 74
h = 3
f1 = 8
f0 = 3
f2 = 7
Thus, Mode = `74 + ((8 - 3)/(2 xx 8 - 3 - 7)) xx 3`
= `74 + 5/6 xx 3`
= `74 + 5/2`
= `(148 + 5)/2`
= `153/2`
= 76.5
OR
(iii) (b) Here N = Σf = 30.
∴ `"N"/2`
= `30/2`
= 15
So, the median class is 74 − 77.
lower limit of median class, l = 74
Class size h = 3
Cumulative frequency Preceding class, Cf = 9
Frequency of medias class = f = 8
Median = `l + (("N"/2 - "Cf"))/"f" xx "h"`
= `74 + ((30/2 - 9))/8 xx 3`
= `74 + ((15 - 9))/8 xx 3`
= `74 + 6/8 xx 3`
= `74 + 18/8`
= 74 + 2.25
= 76.25.