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Henry's law constant for CH3Br(g) is 0.159 mol dm–3 bar–1 at 25°C. What is the solubility of CH3Br(g) in water at the same temperature and partial pressure of 0.164 bar? - Chemistry

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Question

Henry's law constant for CH3Br(g) is 0.159 mol dm–3 bar–1 at 25°C. What is the solubility of CH3Br(g) in water at the same temperature and partial pressure of 0.164 bar?

Short Note

Solution

S = KHP

= 0.159 × 0.164

= 0.026076

= 0.0261

The Solubility of CH3Br(g) in water at same temperature and partial pressure of 0.164 bar will be 0.0261.

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Henry's constant for \[\ce{CH3Br_{(g)}}\] is 0.159 mol dm−3 bar1 25°C. Calculate its solubility in water at 25°C, if its partial pressure is 0.164 bar.


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