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Henry's constant for CHA3BrA(g) is 0.159 mol dm−3 bar−1 25°C. Calculate its solubility in water at 25°C, if its partial pressure is 0.164 bar. - Chemistry

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Question

Henry's constant for \[\ce{CH3Br_{(g)}}\] is 0.159 mol dm−3 bar1 25°C. Calculate its solubility in water at 25°C, if its partial pressure is 0.164 bar.

Numerical

Solution

Given:

Henry's constant for \[\ce{CH3Br_{(g)}}\] = KH = 0.159 mol dm−3 bar1

Partial pressure (P) = 0. 164 bar

To find:

Solubility, S = ?

Formula:

S = KHP

S = 0.159 × 0.164

S = 0.02607 mol L1

∴ Solubility of \[\ce{CH3Br_{(g)}}\] at the given condition, is 0.2607 ≅ 0.0261 mol L1.

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