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Question
How do you explain the presence of all the six carbon atoms in glucose in a straight chain?
Solution
On prolonged heating with \[\ce{HI}\], glucose gives n-hexane.
\[\ce{Glucose ->[HI][Δ] CH3 - CH2 - \underset{(n-Hexane)}{CH2 - CH2} - CH2 - CH3}\]
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