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Question
How is propanoic acid is prepared to start from alcohol?
Short Note
Solution
\[\ce{\underset{(Propan-1-ol)}{CH3 - CH2 - CH2 - OH} ->[H^+/K2Cr2O7] \underset{(Propanoic acid)}{CH3 - CH2 - COOH}}\]
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Nomenclature of Aldehydes and Ketones
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