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Question
How is propanoic acid is prepared to start from an alkyl halide?
Solution
\[\ce{\underset{(Ethyl bromide)}{CH3 - CH2 - Br} ->[Mg/ether] \underset{(Ethyl magnesium bromide)}{CH3 - CH2 - MgBr} ->[(i) CO2][(ii) H^+/H2O] \underset{(Propanoic acid)}{CH3CH2COOH} + MgBr(OH)}\]
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