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Question
How much electricity is required in coulomb for the oxidation of 1 mol of \[\ce{H2O}\] to \[\ce{O2}\]?
Solution
The electrode reaction for 1 mol of \[\ce{H2O}\] is given as –
\[\ce{H2O -> H2 + 1/2O2}\]
i.e., \[\ce{O^{2-} -> 1/2O2 + 2e^-}\]
∴ Amount of electricity required = 2 F
= 2 × 96500 C
= 193000 C
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