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How would you set up a circuit to obtain NOT gate using a transistor? - Physics

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Question

How would you set up a circuit to obtain NOT gate using a transistor?

Short Note

Solution

(1) It has only one input and only one output.

(2) Boolean expression is Y = Ᾱ and is read as “y equals not A”.

Logical symbol of NOT gate.


(3) Realization of NOT gate: The transistor is so biased that the collector voltage VCC = V (Voltage corresponding to 1 state)

The resistors R and RB are so chosen that if the input is low, i.e. 0, the transistor is in the cut-off and hence the voltage appearing at the output will be the same as applied V = 5 V. Hence Y = V (or state I)

If the input is high, the transistor current is in saturation and the net voltage at the output Y is 0 (in state 0).


(4) Truth table for NOT gate:

A Y = Ā
0 1
1 0
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Chapter 14: Semiconductor Electronics - Exercises [Page 92]

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NCERT Exemplar Physics [English] Class 12
Chapter 14 Semiconductor Electronics
Exercises | Q 14.27 | Page 92
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