Advertisements
Advertisements
Question
If a + b + c = 0, then write the value of a3 + b3 + c3.
Sum
Solution
Recall the formula
` a^3 + b^3 +c^3 - 3abc = (a+b+c)(a^2 +b^2 +c^2 -ab-bc - ca)`
When (a + b + c) = 0, we have
`a^3 +b^3 +c^3 -3abc = (a^2 +b^2 +c^2 - ab - bc - ca)`
= 0
`a^3 +b^3 +c^3 - 3abc - 0`
⇒ `a^3 +b^3 +c^3 = 3abc`
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Factorize : x2 + y - xy - x
Factorize `x^2 - 2sqrt2x - 30`
Factorize `8/27 x^3 + 1 + 4/3 x^2 + 2x`
Factorize x3 -12x ( x - 4) - 64
Multiply: (2x + 3y)(2x + 3y)
Multiply: (xy + 2b)(xy - 2b)
Divide: 12x3y - 8x2y2 + 4x2y3 by 4xy
Divide: x2 + 4xy + 4y2 by x + 2y
The area of a rectangular field is 25x2 + 20xy + 3y2 square unit. If its length is 5x + 3y unit, find its breadth, Hence find its perimeter.
If x = 2 and y = 3, then find the value of the following expressions
x + y