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Question
If ABCD is a rectangle with ∠BAC = 32°, find the measure of ∠DBC.
Solution
Figure is given as :
Suppose the diagonals AC and BD intersect at O.
Since, diagonals of a rectangle are equal and they bisect each other.
Therefore, in ΔOAB, we have
OA = OB
Angles opposite to equal sides are equal.
Therefore,
∠OAB = ∠OBA
∠BAC = ∠DBA
But, ∠BAC = 32°
∠DBA = 32°
Now,
∠ABC = 90°
∠DBA + ∠DBC = 90°
32° +∠DBC = 90°
∠DBC = 58°
Hence, the measure of ∠DBC is 58°.
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