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If ๐›ผ, ๐›ฝ Are the Zeroes of the Polynomial `F(X) = X^2 โ€“ 5x + K` Such that ๐›ผ - ๐›ฝ = 1, Find the Value of K = ? - Mathematics

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Question

If ๐›ผ, ๐›ฝ are the zeroes of the polynomial `f(x) = x^2 – 5x + k` such that ๐›ผ - ๐›ฝ = 1, find the value  of k = ? 

Solution

By using the relationship between the zeroes of the quadratic polynomial.
We have  

Sum of zeroes=`(-("Coefficent of x"))/("Cofficient of x"^2)` and Product of zeroes =`("Constant term")/("Coefficent of "x^2)`   

`∴ ∝+β=-(-5)/1` and ∝β=k/1` 

Solving ๐›ผ - ๐›ฝ = 1 and ๐›ผ + ๐›ฝ = 5, we will get 

∝=3 and  ๐›ฝ=2 

Substituting these values in ๐›ผ๐›ฝ =`k/1` we will get 

`k = 6`

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Chapter 2: Polynomials - Exercises 3

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RS Aggarwal Mathematics [English] Class 10
Chapter 2 Polynomials
Exercises 3 | Q 21
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