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If Ax = by = Cz, Prove that X 2 Y Z + Y 2 Z X + Z 2 X Y = B C a 2 + C a B 2 + a B C 2 . - Mathematics

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Question

If ax = by = cz, prove that
`x^2/(yz) + y^2/(zx) + z^2/(xy) = (bc)/a^2 + (ca)/b^2 + (ab)/c^2`.

Sum

Solution

Let ax = by = cz = k, then `x = k/a, y = k/b and z = k/c`
L.H.S. = `x^2/(yz) + y^2/(zx) + z^2/(xy)`
= `k^2/(a^2 xx k/b xx k/c) + k^2/(b^2 xx k/c xx k/a) + k^2/(c^2 xx k/a xx k/b)`
= `(bc)/a^2 + (ca)/b^2 + (ab)/c^2`
= R.H.S.
Hence proved.

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Chapter 8: Ratio and Proportion - Exercise 2

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ICSE Mathematics [English] Class 10
Chapter 8 Ratio and Proportion
Exercise 2 | Q 8
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