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If → a , → a , → C Are Non-coplanar Vectors, Prove that the Following Vectors Are Non-coplanar: 2 → a − → B + 3 → C , → a + → B − 2 → C and → a + → B − 3 → C - Mathematics

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Question

If \[\vec{a}\], \[\vec{a}\], \[\vec{c}\] are non-coplanar vectors, prove that the following vectors are non-coplanar: \[2 \vec{a} - \vec{b} + 3 \vec{c} , \vec{a} + \vec{b} - 2 \vec{c}\text{ and }\vec{a} + \vec{b} - 3 \vec{c}\]

Solution

Let if possible the following vectors are coplanar. Then one of the vector is expressible in terms of the other two.
We have,

\[2 \vec{a} - \vec{b} + 3 \vec{c} = x( \vec{a} + \vec{b} - 2 \vec{c} ) y( \vec{a} + \vec{b} - 3 \vec{c} ) . \]
\[ = \vec{a} (x + y) + \vec{b} (x + y) + \vec{c} ( - 2x - 3y) . \]
\[ \Rightarrow x + y = 2 , x + y = - 1 , - 2x - 3y = 3 .\]
 which is not true, as \[x + y = 2\] ≠ - 1.
Hence the given vectors are non-coplanar.

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Chapter 23: Algebra of Vectors - Exercise 23.8 [Page 66]

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RD Sharma Mathematics [English] Class 12
Chapter 23 Algebra of Vectors
Exercise 23.8 | Q 7.1 | Page 66

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