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Question
If log 2 = 0.3010, log 3 = 0.4771 and log 5 = 0.6990, find the values of: `"log" sqrt(72)`
Solution
`"log" sqrt(72)`
= `"log"(72)^(1/2)`
= `(1)/(2)"log"72`
= `(1)/(2)"log"(2^3 xx 3^2)`
= `(1)/(2)"log"2^3 + (1)/(2)"log"3^2`
= `(3)/(2)"log"2 + (2)/(2)"log"3`
= `(3)/(2)"log"2 + "log"3`
= `(3/2 xx 0.3010) + 0.4771`
= 0.9286.
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