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Question
If n = 5, `bar(x)` = 6, `sumx^2` = 765, then calculate the coefficient of variation.
Solution
Standard deviation (σ) =`sqrt((sumx^2)/"n" - ((sumx)/"n")^2`
= `sqrt(765/5 - (6)^2`
= `sqrt(153 - 36)`
= `sqrt(117)`
σ = 10.816
Coefficient of variation = `sigma/(barx) xx 100%`
= `10.816/6 xx 100%`
= 180.266%
Coefficient of variation = 180.27%
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