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Question
If n(P(A)) = 1024, n(A ∪ B) = 15 and n(P(B)) = 32, then find n(A ∩ B)
Solution
Given n(P(A)) = 1024, n(A ∪ B) = 15, n(P(B)) = 32
n(P(A)) = 1024 = 210 n(A) = 10
n(P(B)) = 32 = 25 = n(B) = 5
n(A ∪ B) = n(A) + n(B) – n(A ∩ B)
15 = 10 + 5 – n(A ∩ B)
15 = 15 – n(A ∩ B)
n(A ∩ B) = 0
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