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Question
If `"p" + (1)/"p" = 6`; find : `"p"^4 + (1)/"p"^4`
Sum
Solution
`("p"^2 + 1/"p"^2)`
= `"p"^4 + (1)/"p"^4 + 2`
⇒ (34)2 = `"p"^4 + (1)/"p"^4 + 2`
⇒ `"p"^4 + (1)/"p"^4`
= 1158 - 2
= 1154.
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