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Question
If `"p" + (1)/"p" = 6`; find : `"p"^3 + (1)/"p"^3`
Sum
Solution
`("p" + 1/"p")^3`
= `"p"^3 + (1)/"p"^3 + 3 ("p" + 1/"p")`
⇒ 216 = `"p"^3 + (1)/"p"^3 + 3(6)`
⇒ `"p"^3 + (1)/"p"^3`
= 216 - 18
= 198.
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