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Question
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find P – Q + R
Solution
P = − 12x2 – 10xy + 5y2
Q = 7x2 + 6xy + 2y2
R = 5x2 + 2xy + 4y2
P – Q + R = (– 12x2 – 10xy + 5y2) – (7x2 + 6xy + 2y2) + (5x2 + 2xy + 4y2)
= – 12x2 – 10xy + 5y2 – 7x2 – 6xy – 2y2 + 5x2 + 2xy + 4y2
= – 12x2 – 7x2 + 5x2 – 10xy – 6xy + 2xy + 5y2 – 2y2 + 4y2
= – 14x2 – 14xy + 7y2
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