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Question
If the prime factorization of a natural number n is 23 ✕ 32 ✕ 52 ✕ 7, write the number of consecutive zeros in n.
Solution
Since, it is given that
`n= 2^3xx3^2xx5^2xx7`
`n= 8xx9xx25xx7`
`n=(7xx9xx2)xx(4xx25)`
`n=(7xx9xx2)xx100`
`n=(7xx9xx2)xx100`
`n= 12600`
Hence the number of consecutive zeroes are 2.
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