Advertisements
Advertisements
Question
If the product of two numbers is 1080 and their HCF is 30, find their LCM.
Solution
It is given that the product of two numbers is 1080.
Let the two numbers be a and b.
Therefore,
a x b = 1080
HCF is 30.
We need to find the LCM
We know that the product of two numbers is equal to the product of the HCF and LCM.
Thus,
`LCM= (axxb)/(HCF)`
`LCM = (1080)/30`
`LCM=36`
Hence the LCM is 36 .
APPEARS IN
RELATED QUESTIONS
Consider the number 6n where n is a natural number. Check whether there is any value of n ∈ N for which 6n is divisible by 7.
Express the number as a product of its prime factor:
140
Find the LCM and HCF of the following integers by applying the prime factorisation method.
12, 15 and 21
Determine the prime factorisation of each of the following positive integer:
58500
Write down the decimal expansions of the following rational numbers by writing their denominators in the form 2m × 5n, where, m, n are non-negative integers.\[\frac{13}{125}\]
Write the sum of the exponents of prime factors in the prime factorization of 98.
The largest number which divides 60 and 75, leaving remainders 8 and 10 respectively, is ______.
If the HCF of 65 and 117 is expressible in the form 65m – 117, then the value of m is ______.
Find the HCF and LCM of 26, 65 and 117, using prime factorisation.
The HCF of two numbers 65 and 104 is 13. If LCM of 65 and 104 is 40x, then the value of x is ______.